Comparing two lists and printing the list in Python

Question

I have two lists Z1 and Z2. I am comparing these two lists and if at least one sublist of Z1 appears in Z2, I want to print full Z1. I present the current and expected output.

Z1=[[0, 4], [0, 5], [4, 5]]
Z2=[[6, 5], [4, 9], [4, 8], [5, 3], [0,4]]

for i in range(0,len(Z1)):
    if (Z1[i]==Z2[i]):
        print("Z1 =",Z1)

The current output is

(Blank)

The expected output is

Z1=[[0, 4], [0, 5], [4, 5]]

Answer 1

An rather elegant solution can be using sets and their intersection:

Z1=[[0, 4], [0, 5], [4, 5]]
Z2=[[6, 5], [4, 9], [4, 8], [5, 3], [0,4]]

zs1 = set(map(tuple, Z1))
zs2 = set(map(tuple, Z2))

if (zs1 & zs2):
    print("Z1 =",Z1)

Answer 2

You are not looking over all of Z2 at most you arrive at i=2 so you never arrive at the last item in Z2 which is the one you are looking for (which should be i=4, but len(Z1) < 4).

Just loop over both, brute force solution:

>>> for z1 in Z1:
...     for z2 in Z2:
...             if z1 == z2:
...                     print("Z1 =",Z1)
...                     break
... 
Z1 = [[0, 4], [0, 5], [4, 5]]