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Comparing string and boolean in Expression language

I have this behaviour I do not really understand

${someVar}
${someVar.class.name}      
${someVar == 'error'}

outputs

false
java.lang.Boolean
true
  1. How can it be exlpained?
  2. What it the correct way to write the test in order to first test if the two 'things' have the same type and then if their value is the same?
like image 962
Paolo Avatar asked Nov 17 '11 14:11

Paolo


2 Answers

This is the behaviour of the language as defined in the EL specification:

A {==,!=,eq,ne} B

  • other rules elided
  • If A or B is Boolean coerce both A and B to Boolean, apply operator

Coerce A to Boolean

  • If A is null or "", return false
  • Otherwise, if A is a Boolean, return A
  • Otherwise, if A is a String, and Boolean.valueOf(A) does not throw an exception, return it
  • Otherwise, error

So, the string literal is coerced to a boolean via Boolean.valueOf("error") which returns false.

like image 55
McDowell Avatar answered Oct 23 '22 14:10

McDowell


If one of the both sides in EL is a Boolean (or boolean) and the other side is a String, then the String will be parsed to Boolean by Boolean#valueOf() whose javadoc says the following:

Returns a Boolean with a value represented by the specified string. The Boolean returned represents a true value if the string argument is not null and is equal, ignoring case, to the string "true".

So, it returns false and this is indeed equal to false.

You need to rewrite your EL expression to take into account that the type can be both a boolean and a string, or just to stick to a single type and not to mix types in a single attribute.

like image 33
BalusC Avatar answered Oct 23 '22 15:10

BalusC