Walk with me ..
Integer x = 23; Integer y = 23; if (x == y) System.out.println("what else"); // All is well as expected else System.out.println("...");
While
Integer x = someObject.getIndex(); Integer y = someOtherObject.getSomeOtherIndex(); if (x == y) System.out.println("what else"); else System.out.println("..."); // Prints this
Hmm ... I try casting to int
int x = someObject.getIndex(); int y = someOtherObject.getSomeOtherIndex() if (x == y) System.out.println("what else"); // works fine else System.out.println("...");
Are they both Integers?
System.out.println(x.getClass().getName()); // java.lang.Integer System.out.println(y.getClass().getName()); // java.lang.Integer System.out.println(someObject.getIndex()); // java.lang.Integer System.out.println(someOtherObject.getSomeOtherIndex()); // java.lang.Integer
What do you guys think? What would explain something like this?
Syntax : public static int compare(int x, int y) Parameter : x : the first int to compare y : the second int to compare Return : This method returns the value zero if (x==y), if (x < y) then it returns a value less than zero and if (x > y) then it returns a value greater than zero. Example :To show working of java.
compare(int x, int y) compare() compares two int values numerically and returns an integer value. If x>y then the method returns an int value greater than zero. If x=y then the method returns zero.
To compare integer values in Java, we can use either the equals() method or == (equals operator). Both are used to compare two values, but the == operator checks reference equality of two integer objects, whereas the equal() method checks the integer values only (primitive and non-primitive).
In Java, int is a primitive data type while Integer is a Wrapper class.
You're comparing Integer
values, which are references. You're coming up with those references via autoboxing. For some values (guaranteed for -128 to 127) the JRE maintains a cache of Integer
objects. For higher values, it doesn't. From section 5.1.7 of the JLS:
If the value p being boxed is true, false, a byte, or a char in the range \u0000 to \u007f, or an int or short number between -128 and 127 (inclusive), then let r1 and r2 be the results of any two boxing conversions of p. It is always the case that r1 == r2.
Ideally, boxing a given primitive value p, would always yield an identical reference. In practice, this may not be feasible using existing implementation techniques. The rules above are a pragmatic compromise. The final clause above requires that certain common values always be boxed into indistinguishable objects. The implementation may cache these, lazily or eagerly. For other values, this formulation disallows any assumptions about the identity of the boxed values on the programmer's part. This would allow (but not require) sharing of some or all of these references.
This ensures that in most common cases, the behavior will be the desired one, without imposing an undue performance penalty, especially on small devices. Less memory-limited implementations might, for example, cache all char and short values, as well as int and long values in the range of -32K to +32K.
Moral: don't compare Integer
references when you're interested in the underlying int
values. Use .equals()
or get the int
values first.
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