Compare two primitive long variables in java

Question

The title is pretty self-explanatory. I'm moving from C# to Java. I have an object and a getter method which returns its ID. I want to compare the ids of two objects of the same type and check if the values of their ids are equal.

tried:

obj.getId() == obj1.getId();

---

Long id1 = obj.getId();
Long id2 = obj1.getId();

assertTrue(id1.equals(id2))

---

assertTrue(id1== id2)

Answer 1

To compare two primitive long you can simply use ==

Example:

long x = 1L;
long y = 1L;

if (x == y) {
 System.out.println("value of x and y are same");
}

To compare two Long objects you can use Long.compare(long x, long y). This method was added in java 1.7. Below is the method implementation:

public static int compare(long x, long y) {
        return (x < y) ? -1 : ((x == y) ? 0 : 1);
}

Example:

Long x = new Long(1);
Long y = new Long(1);
if (Long.compare(x,y) == 0) {
  System.out.println(values of x and y are same);
}