Compare two dictionaries, remove key/value pair in one dict if it exists in the other

Question

I have two dictionaries. One looks like this:

dict1 = {'ana': 'http://ted.com', 'louise': 'http://reddit.com', 'sarah':'http://time.com'}

The other one looks like this:

dict2 = {'patricia': 'http://yahoo.com', 'ana': 'http://ted.com',
         'louise': 'http://reddit.com', 'florence': 'http://white.com'}

I need to compare the two dictionaries, and eliminate from dict2 any key/value pair already present in dict1

As you can see, Ana and Louise already exist in dict1, so I'd like to automatically delete it from dict2 The output expected would contain only elements unique to dict2 and not already present in dict1, and would look like:

dict2 = {'patricia': 'http://yahoo.com', 'florence': 'http://white.com'}

I don't need to do anything about Sarah being in dict1. I only care about comparing dict2 with dict1 to remove duplicates.

Extra info:

I tried to loop over the dicts in many different ways but it gave me two types of errors: not hashable type or dict content changed during action.

I also tried to make each into a list and combine the lists, but the end result is another list and I don't know how to turn a list back into a dictionary.

Answer 1

Jim's answer removes items if the keys match. I think you wanted to remove if both key and value matched. This is actually very easy since you're using Python 3:

>>> dict(dict2.items() - dict1.items())
{'florence': 'http://white.com', 'patricia': 'http://yahoo.com'}

It works because dict_items objects treat subtraction operations as set differences.