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Strings s1 and s2 will always be of length 1 or higher.
How can I speed this up?
int l1 = s1.length();
if (l1 > 3) { l1 = 3; }
if (s2.startsWith(s1.substring(0,l1)))
{
// do something..
}
Regex maybe?
840
You can compare two Strings in Java using the compareTo() method, equals() method or == operator. The compareTo() method compares two strings. The comparison is based on the Unicode value of each character in the strings.
There are three ways to compare String in Java: By Using equals() Method. By Using == Operator. By compareTo() Method.
tf = strncmpi( s1,s2 , n ) compares up to n characters of s1 and s2 , ignoring any differences in letter case. The function returns 1 ( true ) if the two are identical and 0 ( false ) otherwise.
This seems pretty reasonable. Is this really too slow for you? You sure it's not premature optimization?
101
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