Combining (cbind) vectors of different length

Question

I have several vectors of unequal length and I would like to cbind them. I've put the vectors into a list and I have tried to combine the using do.call(cbind, ...):

nm <- list(1:8, 3:8, 1:5) do.call(cbind, nm)  #      [,1] [,2] [,3] # [1,]    1    3    1 # [2,]    2    4    2 # [3,]    3    5    3 # [4,]    4    6    4 # [5,]    5    7    5 # [6,]    6    8    1 # [7,]    7    3    2 # [8,]    8    4    3 # Warning message: #   In (function (..., deparse.level = 1)  : #         number of rows of result is not a multiple of vector length (arg 2) 

As expected, the number of rows in the resulting matrix is the length of the longest vector, and the values of the shorter vectors are recycled to make up for the length.

Instead I'd like to pad the shorter vectors with NA values to obtain the same length as the longest vector. I'd like the matrix to look like this:

#      [,1] [,2] [,3] # [1,]    1    3    1 # [2,]    2    4    2 # [3,]    3    5    3 # [4,]    4    6    4 # [5,]    5    7    5 # [6,]    6    8    NA # [7,]    7    NA   NA # [8,]    8    NA   NA 

How can I go about doing this?

Answer 1

You can use indexing, if you index a number beyond the size of the object it returns NA. This works for any arbitrary number of rows defined with foo:

nm <- list(1:8,3:8,1:5)  foo <- 8  sapply(nm, '[', 1:foo) 

EDIT:

Or in one line using the largest vector as number of rows:

sapply(nm, '[', seq(max(sapply(nm,length)))) 

From R 3.2.0 you may use lengths ("get the length of each element of a list") instead of sapply(nm, length):

sapply(nm, '[', seq(max(lengths(nm)))) 

Answer 2

You should fill vectors with NA before calling do.call.

nm <- list(1:8,3:8,1:5)  max_length <- max(unlist(lapply(nm,length))) nm_filled <- lapply(nm,function(x) {ans <- rep(NA,length=max_length);                                     ans[1:length(x)]<- x;                                     return(ans)}) do.call(cbind,nm_filled)