Combinations from dictionary with list values using Python

Question

I have the following incoming value:

variants = {   "debug" : ["on", "off"],   "locale" : ["de_DE", "en_US", "fr_FR"],   ... } 

I want to process them so I get the following result:

combinations = [   [{"debug":"on"},{"locale":"de_DE"}],   [{"debug":"on"},{"locale":"en_US"}],   [{"debug":"on"},{"locale":"fr_FR"}],   [{"debug":"off"},{"locale":"de_DE"}],   [{"debug":"off"},{"locale":"en_US"}],   [{"debug":"off"},{"locale":"fr_FR"}] ] 

This should work with arbitrary length of keys in the dictionary. Played with itertools in Python, but did not found anything matching these requirements.

Answer 1

import itertools as it  varNames = sorted(variants) combinations = [dict(zip(varNames, prod)) for prod in it.product(*(variants[varName] for varName in varNames))] 

Hm, this returns:

[{'debug': 'on', 'locale': 'de_DE'},  {'debug': 'on', 'locale': 'en_US'},  {'debug': 'on', 'locale': 'fr_FR'},  {'debug': 'off', 'locale': 'de_DE'},  {'debug': 'off', 'locale': 'en_US'},  {'debug': 'off', 'locale': 'fr_FR'}] 

which is probably not exactly, what you want. Let me adapt it...

combinations = [ [ {varName: val} for varName, val in zip(varNames, prod) ] for prod in it.product(*(variants[varName] for varName in varNames))] 

returns now:

[[{'debug': 'on'}, {'locale': 'de_DE'}],  [{'debug': 'on'}, {'locale': 'en_US'}],  [{'debug': 'on'}, {'locale': 'fr_FR'}],  [{'debug': 'off'}, {'locale': 'de_DE'}],  [{'debug': 'off'}, {'locale': 'en_US'}],  [{'debug': 'off'}, {'locale': 'fr_FR'}]] 

Voilà ;-)

Answer 2

combinations = [[{key: value} for (key, value) in zip(variants, values)]                  for values in itertools.product(*variants.values())]  [[{'debug': 'on'}, {'locale': 'de_DE'}],  [{'debug': 'on'}, {'locale': 'en_US'}],  [{'debug': 'on'}, {'locale': 'fr_FR'}],  [{'debug': 'off'}, {'locale': 'de_DE'}],  [{'debug': 'off'}, {'locale': 'en_US'}],  [{'debug': 'off'}, {'locale': 'fr_FR'}]]