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Closures in auto executing functions vs objects

Let us say I have the following:

var foo = (function(){
    var bar = 0;
    return {
       getBar: function(){
           return bar;
       },
       addOne: function(){
           bar++;
       },
       addRandom: function(rand){
           bar += rand;
       }
    }
})();

And I have the following:

var foo2 = function(){
    var bar = 0;
    this.getBar = function(){
           return bar;
       };
    this.addOne = function(){
           bar++;
       };
    this.addRandom = function(rand){
           bar += rand;
       }
};

Is the only difference in executing the functions a new?

alert(foo.getBar()); //0
foo.addOne();
foo.addRandom(32);
alert(foo.getBar()); //33

var foo2_obj = new foo2;
alert(foo2_obj.getBar());//0
foo2_obj.addOne();
foo2_obj.addRandom(32);
alert(foo2_obj.getBar());//33

They both out put the exact same thing.

So what is the difference in the long run?

What can one do that the other cannot?

Fiddle Demo of the above: http://jsfiddle.net/maniator/YtBpe/

like image 460
Naftali Avatar asked Nov 22 '11 18:11

Naftali


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2 Answers

In the first one you can only create the object once, while with the second one you can create as many objects as you like. I.E. the first one is effectively a singleton.

Note that closures are not ok for the second one. Every time you instantiate it you are creating the functions all over again and waste a ton of memory. The prototype object is intended to counter this, where you can create the functions once outside a function scope and no accidental closures are created.

function foo2(){
    this._bar = 0;
}

foo2.prototype = {

    constructor: foo2,

    getBar: function(){
        return this._bar;
    },

    addOne: function(){
        this._bar++;
    },

    addRandom:function(rand){
        this._bar += rand;
    }

};

Then:

var a = new foo2, b = new foo2, c = new foo2;

Creates three instances which have their own _bar but share the same functionality.

jsperf

You can "compare" all of this to PHP, some of the code won't even run but it's "equivalent" in principle:


var foo = (function(){
    var bar = 0;
    return {
       getBar: function(){
           return bar;
       },
       addOne: function(){
           bar++;
       },
       addRandom: function(rand){
           bar += rand;
       }
    }
})();

is roughly "equivalent" to this in PHP:

$foo = new stdClass;

$foo->bar = 0;

$foo->getBar = function(){
    return $this->bar;
};

$foo->addOne = function(){
    $this->bar++;
}

$foo->addRandom = function($rand){
    $this->bar += $rand;
}

var foo2 = function(){
    var bar = 0;
    this.getBar = function(){
        return bar;
    };
    this.addOne = function(){
        bar++;
    };
    this.addRandom = function(rand){
        bar += rand;
    }
};

Is roughly "equivalent" to this in PHP:

Class foo2 {


    public function __construct(){
    $bar = 0;

        $this->getBar = function(){
            return $bar;
        };
        $this->addOne = function(){
            $bar++;
        };
        $this->addRandom = function($rand){
            $bar += rand;
        };


    }

}

function foo2(){
    this._bar = 0;
}

foo2.prototype = {

    constructor: foo2,

    getBar: function(){
        return this._bar;
    },

    addOne: function(){
        this._bar++;
    },

    addRandom:function(rand){
        this._bar += rand;
    }

};

Is roughly "equivalent" to this in PHP:

Class foo2 {

    public $_bar;

    public function __construct(){
        $this->_bar = 0;    
    }

    public function getBar(){
        return $this->_bar;    
    }

    public function addOne(){
        $this->_bar++
    }

    public function addRandom($rand){
        $this->_bar += $rand;
    }

}

...and is the only one that is close to OOP in the three above examples


like image 71
Esailija Avatar answered Oct 21 '22 19:10

Esailija


The only difference is that foo will be a generic Object, whereas foo2_obj will identify as a foo2 when checking its type (i.e. foo2_obj.constructor == foo2 will be true, while the equivalent on foo is foo.constructor == Object).

Of course, there's an important distinction between foo and foo2 - foo is an object, while foo2 is a function (intended for use as a constructor). Thus, it is trivial to make as many instances of foo2 (of which foo2_obj is one), while the idea of creating "instances" of foo doesn't really make sense - the best you could do are copies (which is more difficult than calling a constructor).

Due to the copying/creating instances distinction, the second approach allows for real OO programming with prototype chains, while the first makes such things much more difficult (and ill-advised).

like image 25
Aaron Dufour Avatar answered Oct 21 '22 19:10

Aaron Dufour