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Client to send SOAP request and receive response

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How do I get a response from a SOAP request?

HTTP ResponseClick the 'RAW' Tab in SOAP-UI Response Window to understand how the response is sent via HTTP. After processing the request, the http response code (200) is shown which means it is a success. The web-server has processed it successfully.


I normally use another way to do the same

using System.Xml;
using System.Net;
using System.IO;

public static void CallWebService()
{
    var _url = "http://xxxxxxxxx/Service1.asmx";
    var _action = "http://xxxxxxxx/Service1.asmx?op=HelloWorld";

    XmlDocument soapEnvelopeXml = CreateSoapEnvelope();
    HttpWebRequest webRequest = CreateWebRequest(_url, _action);
    InsertSoapEnvelopeIntoWebRequest(soapEnvelopeXml, webRequest);

    // begin async call to web request.
    IAsyncResult asyncResult = webRequest.BeginGetResponse(null, null);

    // suspend this thread until call is complete. You might want to
    // do something usefull here like update your UI.
    asyncResult.AsyncWaitHandle.WaitOne();

    // get the response from the completed web request.
    string soapResult;
    using (WebResponse webResponse = webRequest.EndGetResponse(asyncResult))
    {
        using (StreamReader rd = new StreamReader(webResponse.GetResponseStream()))
        {
            soapResult = rd.ReadToEnd();
        }
        Console.Write(soapResult);        
    }
}

private static HttpWebRequest CreateWebRequest(string url, string action)
{
    HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
    webRequest.Headers.Add("SOAPAction", action);
    webRequest.ContentType = "text/xml;charset=\"utf-8\"";
    webRequest.Accept = "text/xml";
    webRequest.Method = "POST";
    return webRequest;
}

private static XmlDocument CreateSoapEnvelope()
{
    XmlDocument soapEnvelopeDocument = new XmlDocument();
    soapEnvelopeDocument.LoadXml(
    @"<SOAP-ENV:Envelope xmlns:SOAP-ENV=""http://schemas.xmlsoap.org/soap/envelope/"" 
               xmlns:xsi=""http://www.w3.org/1999/XMLSchema-instance"" 
               xmlns:xsd=""http://www.w3.org/1999/XMLSchema"">
        <SOAP-ENV:Body>
            <HelloWorld xmlns=""http://tempuri.org/"" 
                SOAP-ENV:encodingStyle=""http://schemas.xmlsoap.org/soap/encoding/"">
                <int1 xsi:type=""xsd:integer"">12</int1>
                <int2 xsi:type=""xsd:integer"">32</int2>
            </HelloWorld>
        </SOAP-ENV:Body>
    </SOAP-ENV:Envelope>");
    return soapEnvelopeDocument;
}

private static void InsertSoapEnvelopeIntoWebRequest(XmlDocument soapEnvelopeXml, HttpWebRequest webRequest)
{
    using (Stream stream = webRequest.GetRequestStream())
    {
        soapEnvelopeXml.Save(stream);
    }
}

I got this simple solution here:

Sending SOAP request and receiving response in .NET 4.0 C# without using the WSDL or proxy classes:

class Program
    {
        /// <summary>
        /// Execute a Soap WebService call
        /// </summary>
        public static void Execute()
        {
            HttpWebRequest request = CreateWebRequest();
            XmlDocument soapEnvelopeXml = new XmlDocument();
            soapEnvelopeXml.LoadXml(@"<?xml version=""1.0"" encoding=""utf-8""?>
                <soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
                  <soap:Body>
                    <HelloWorld xmlns=""http://tempuri.org/"" />
                  </soap:Body>
                </soap:Envelope>");

            using (Stream stream = request.GetRequestStream())
            {
                soapEnvelopeXml.Save(stream);
            }

            using (WebResponse response = request.GetResponse())
            {
                using (StreamReader rd = new StreamReader(response.GetResponseStream()))
                {
                    string soapResult = rd.ReadToEnd();
                    Console.WriteLine(soapResult);
                }
            }
        }
        /// <summary>
        /// Create a soap webrequest to [Url]
        /// </summary>
        /// <returns></returns>
        public static HttpWebRequest CreateWebRequest()
        {
            HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(@"http://localhost:56405/WebService1.asmx?op=HelloWorld");
            webRequest.Headers.Add(@"SOAP:Action");
            webRequest.ContentType = "text/xml;charset=\"utf-8\"";
            webRequest.Accept = "text/xml";
            webRequest.Method = "POST";
            return webRequest;
        }

        static void Main(string[] args)
        {
            Execute();
        }
    }

I think there is a simpler way:

 public async Task<string> CreateSoapEnvelope()
 {
      string soapString = @"<?xml version=""1.0"" encoding=""utf-8""?>
          <soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
              <soap:Body>
                  <HelloWorld xmlns=""http://tempuri.org/"" />
              </soap:Body>
          </soap:Envelope>";

          HttpResponseMessage response = await PostXmlRequest("your_url_here", soapString);
          string content = await response.Content.ReadAsStringAsync();

      return content;
 }

 public static async Task<HttpResponseMessage> PostXmlRequest(string baseUrl, string xmlString)
 {
      using (var httpClient = new HttpClient())
      {
          var httpContent = new StringContent(xmlString, Encoding.UTF8, "text/xml");
          httpContent.Headers.Add("SOAPAction", "http://tempuri.org/HelloWorld");

          return await httpClient.PostAsync(baseUrl, httpContent);
       }
 }

The best practice is to reference the WSDL and use it like a web service reference. It's easier and works better, but if you don't have the WSDL, the XSD definitions are a good piece of code.