HTTP ResponseClick the 'RAW' Tab in SOAP-UI Response Window to understand how the response is sent via HTTP. After processing the request, the http response code (200) is shown which means it is a success. The web-server has processed it successfully.
I normally use another way to do the same
using System.Xml;
using System.Net;
using System.IO;
public static void CallWebService()
{
var _url = "http://xxxxxxxxx/Service1.asmx";
var _action = "http://xxxxxxxx/Service1.asmx?op=HelloWorld";
XmlDocument soapEnvelopeXml = CreateSoapEnvelope();
HttpWebRequest webRequest = CreateWebRequest(_url, _action);
InsertSoapEnvelopeIntoWebRequest(soapEnvelopeXml, webRequest);
// begin async call to web request.
IAsyncResult asyncResult = webRequest.BeginGetResponse(null, null);
// suspend this thread until call is complete. You might want to
// do something usefull here like update your UI.
asyncResult.AsyncWaitHandle.WaitOne();
// get the response from the completed web request.
string soapResult;
using (WebResponse webResponse = webRequest.EndGetResponse(asyncResult))
{
using (StreamReader rd = new StreamReader(webResponse.GetResponseStream()))
{
soapResult = rd.ReadToEnd();
}
Console.Write(soapResult);
}
}
private static HttpWebRequest CreateWebRequest(string url, string action)
{
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url);
webRequest.Headers.Add("SOAPAction", action);
webRequest.ContentType = "text/xml;charset=\"utf-8\"";
webRequest.Accept = "text/xml";
webRequest.Method = "POST";
return webRequest;
}
private static XmlDocument CreateSoapEnvelope()
{
XmlDocument soapEnvelopeDocument = new XmlDocument();
soapEnvelopeDocument.LoadXml(
@"<SOAP-ENV:Envelope xmlns:SOAP-ENV=""http://schemas.xmlsoap.org/soap/envelope/""
xmlns:xsi=""http://www.w3.org/1999/XMLSchema-instance""
xmlns:xsd=""http://www.w3.org/1999/XMLSchema"">
<SOAP-ENV:Body>
<HelloWorld xmlns=""http://tempuri.org/""
SOAP-ENV:encodingStyle=""http://schemas.xmlsoap.org/soap/encoding/"">
<int1 xsi:type=""xsd:integer"">12</int1>
<int2 xsi:type=""xsd:integer"">32</int2>
</HelloWorld>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>");
return soapEnvelopeDocument;
}
private static void InsertSoapEnvelopeIntoWebRequest(XmlDocument soapEnvelopeXml, HttpWebRequest webRequest)
{
using (Stream stream = webRequest.GetRequestStream())
{
soapEnvelopeXml.Save(stream);
}
}
I got this simple solution here:
Sending SOAP request and receiving response in .NET 4.0 C# without using the WSDL or proxy classes:
class Program
{
/// <summary>
/// Execute a Soap WebService call
/// </summary>
public static void Execute()
{
HttpWebRequest request = CreateWebRequest();
XmlDocument soapEnvelopeXml = new XmlDocument();
soapEnvelopeXml.LoadXml(@"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
<soap:Body>
<HelloWorld xmlns=""http://tempuri.org/"" />
</soap:Body>
</soap:Envelope>");
using (Stream stream = request.GetRequestStream())
{
soapEnvelopeXml.Save(stream);
}
using (WebResponse response = request.GetResponse())
{
using (StreamReader rd = new StreamReader(response.GetResponseStream()))
{
string soapResult = rd.ReadToEnd();
Console.WriteLine(soapResult);
}
}
}
/// <summary>
/// Create a soap webrequest to [Url]
/// </summary>
/// <returns></returns>
public static HttpWebRequest CreateWebRequest()
{
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(@"http://localhost:56405/WebService1.asmx?op=HelloWorld");
webRequest.Headers.Add(@"SOAP:Action");
webRequest.ContentType = "text/xml;charset=\"utf-8\"";
webRequest.Accept = "text/xml";
webRequest.Method = "POST";
return webRequest;
}
static void Main(string[] args)
{
Execute();
}
}
I think there is a simpler way:
public async Task<string> CreateSoapEnvelope()
{
string soapString = @"<?xml version=""1.0"" encoding=""utf-8""?>
<soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
<soap:Body>
<HelloWorld xmlns=""http://tempuri.org/"" />
</soap:Body>
</soap:Envelope>";
HttpResponseMessage response = await PostXmlRequest("your_url_here", soapString);
string content = await response.Content.ReadAsStringAsync();
return content;
}
public static async Task<HttpResponseMessage> PostXmlRequest(string baseUrl, string xmlString)
{
using (var httpClient = new HttpClient())
{
var httpContent = new StringContent(xmlString, Encoding.UTF8, "text/xml");
httpContent.Headers.Add("SOAPAction", "http://tempuri.org/HelloWorld");
return await httpClient.PostAsync(baseUrl, httpContent);
}
}
The best practice is to reference the WSDL and use it like a web service reference. It's easier and works better, but if you don't have the WSDL, the XSD definitions are a good piece of code.
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