CInt does not round Double value consistently - how can I remove the fractional part?

Question

I've stumbled upon an issue with CInt and converting a double to an integer.

The issue is the following:

CInt(10.5)  'Result is 10
CInt(10.51) 'Result it 11, but I expected 10...

I got used to C# style conversion where (int) 10.51 is 10.

As pointed out in the question about Integer.Parse vs CInt, the result is just rounded in some fashion.

However, all I need is to get only integer part and throw away the fractional one. How can I achieve such type of conversion in VB.NET? After some research I see that I can use the Fix() function to do the trick, but is it the best choice?

Answer 1

You may use Int or Fix functions but return value type of these functions is double so you have to convert it to Integer if option strict is on.

  no = Convert.ToInt32(Int(10.51))