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Why is this not possible?
if(!empty( _MY_CONST)){
...
But yet this is:
$my_const = _MY_CONST;
if(!empty($my_const)){
...
define( 'QUOTA_MSG' , '' ); // There is currently no message to show
$message = QUOTA_MSG;
if(!empty($message)){
echo $message;
}
I just wanted to make it a little cleaner by just referencing the constant itself.
693
"0" is considered as no value or empty value.
PHP empty() Function The empty() function checks whether a variable is empty or not. This function returns false if the variable exists and is not empty, otherwise it returns true. The following values evaluates to empty: 0.
We can use empty() function to check whether a string is empty or not. The function is used to check whether the string is empty or not. It will return true if the string is empty. Parameter: Variable to check whether it is empty or not.
A variable is considered empty if it does not exist or if its value equals false .
if (!empty(constant('MY_CONST')) {
...
}
mixed constant ( string $name )
Return the value of the constant indicated by $name, or NULL if the constant is not defined
http://php.net/manual/en/function.constant.php
193
See the manual: empty() is a language construct, not a function.
empty()only checks variables as anything else will result in a parse error. In other words, the following will not work:empty(trim($name)).
So you'll have to use a variable - empty() is really what you want in the first place? It would return true when the constant's value is "0" for example.
Maybe you need to test for the existence of the constant using defined() instead?
22
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