Check state of button in tkinter

Question

On a tkinter GUI I want to print different messages on a canvas depending on the state of a button I hover over. If the button itself is DISABLED, I want to display another message on the canvas than when the button is NORMAL. I have this (stripped) relevant code:

from tkinter import *

class app:
    def __init__(self):
        self.window = Tk()
        self.button = Button(self.window,text="Button",command=self.someCommand,state=DISABLED)

        self.button.bind("<Enter>", self.showText)
        self.button.bind("<Leave>", self.hideText)

        self.window.mainloop()

    def showText(self):
        if self.button["state"] == DISABLED:
            #print this text on a canvas
        else:
            #print that text on a canvas

    def hideText(self):
        #remove text    

def main()
    instance = app()

main()

This always draws 'that text' on the canvas, instead of 'this text'

I have tried the following too:

 self.button['state']
 == 'disabled'
 == 'DISABLED'

if I print:

print(self.button["state"] == DISABLED)

it gives me:

False

Changing the state using:

self.button["state"] = NORMAL

works as I would expect.

I have read through a few topics here but none seem to answer the question to why the if-statement doesn't work.

Answer 1

After some more research I finally got a solution.

print(self.button['state'])

prints:

disabled

So I could use:

state = str(self.button['state'])
if state == 'disabled':
    #print the correct text!