Question: How do I check the size in bytes of a variable using Julia?
What I've tried: In Matlab, the whos()
function provided this information, but in Julia that just provides the variable names and module. Browsing the standard library in the Julia manual, sizeof()
looked promising, but it only appears to provide the size of the canonical binary representation, rather than the current variable.
returns the size of the array times the element size.
julia> x = [1 2 3 4]
1x4 Array{Int64,2}:
1 2 3 4
julia> sizeof(x)
32
julia> x = Int8[1 2 3 4]
1x4 Array{Int8,2}:
1 2 3 4
julia> sizeof(x)
4
returns chunks; each chunk is 8 bytes so can represent up to 64 bits
julia> x = BitArray(36);
julia> sizeof(x)
8
julia> x = BitArray(65);
julia> sizeof(x)
16
return the number of characters in the string (1 byte/char).
julia> sizeof("hello world")
11
Same as above but with 2 and 4 bytes/character respectively.
julia> x = utf32("abcd");
julia> sizeof(x)
16
sizeof(s::SubString{ASCIIString}) at string.jl:590
sizeof(s::SubString{UTF8String}) at string.jl:591
sizeof(s::RepString) at string.jl:690
sizeof(s::RevString{T<:AbstractString}) at string.jl:737
sizeof(s::RopeString) at string.jl:802
sizeof(s::AbstractString) at string.jl:71
returns the number of bytes each variable uses
julia> x = Int64(0);
julia> sizeof(x)
8
julia> x = Int8(0);
julia> sizeof(x)
1
julia> x = Float16(0);
julia> sizeof(x)
2
julia> x = sizeof(Float64)
8
one would expect, but note that Julia characters are wide characters
julia> sizeof('a')
4
For cases where the layout is more complex and/or not contiguous. Here's a function that will iterate over the fields of a variable (if any) and return of sum of all of the sizeof results which should be the total number of bytes allocated.
getBytes(x::DataType) = sizeof(x);
function getBytes(x)
total = 0;
fieldNames = fieldnames(typeof(x));
if fieldNames == []
return sizeof(x);
else
for fieldName in fieldNames
total += getBytes(getfield(x,fieldName));
end
return total;
end
end
create an instance of a random-ish type...
julia> type X a::Vector{Int64}; b::Date end
julia> x = X([i for i = 1:50],now())
X([1,2,3,4,5,6,7,8,9,10 … 41,42,43,44,45,46,47,48,49,50],2015-02-09)
julia> getBytes(x)
408
It also includes the overhead from the struct as seen in the examples.
julia> struct Foo a; b end
julia> Base.summarysize(ones(10000))
80040
julia> Base.summarysize(Foo(ones(10000), 1))
80064
julia> Base.summarysize(Foo(ones(10000), Foo(ones(10, 10), 1)))
80920
However, care should be taken as the function is non-exported and might not be future proof
In julia 1.6, varinfo()
shows sizes:
julia> a = 1;
julia> v = ones(10000);
julia> varinfo()
name size summary
–––––––––––––––– ––––––––––– –––––––––––––––––––––––––––––
Base Module
Core Module
InteractiveUtils 250.022 KiB Module
Main Module
ans 78.164 KiB 10000-element Vector{Float64}
v 78.164 KiB 10000-element Vector{Float64}
a 8 bytes Int64
For specific variables, either use pattern matching (r"..."
is a regular expression):
julia> varinfo(r"^v$")
name size summary
–––– –––––––––– –––––––––––––––––––––––––––––
v 78.164 KiB 10000-element Vector{Float64}
or combine the Base.summarysize
from Korbinian answer with Base.format_bytes
:
julia> pretty_summarysize(x) = Base.format_bytes(Base.summarysize(x))
pretty_summarysize (generic function with 1 method)
julia> pretty_summarysize(v)
"78.164 KiB"
Edit: beware that summarysize
had a bug, at least in 1.5.3 and 1.6.1. varinfo
was affected as well. It is fixed (tested with 1.7.3
).
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