check os.path.isfile(filename) with case sensitive in python

Question

I need to check whether the given file is exist or not with case sensitive.

file = "C:\Temp\test.txt"
if os.path.isfile(file):
    print "exist..."
else:
    print "not found..."

TEST.TXT file is present under C:\Temp folder. but the script showing "file exist" output for file = "C:\Temp\test.txt", it should show "not found".

Thanks.

Answer 1

List all names in the directory instead, so you can do a case-sensitive match:

def isfile_casesensitive(path):
    if not os.path.isfile(path): return False   # exit early
    directory, filename = os.path.split(path)
    return filename in os.listdir(directory)

if isfile_casesensitive(file):
    print "exist..."
else:
    print "not found..."

Demo:

>>> import os
>>> file = os.path.join(os.environ('TMP'), 'test.txt')
>>> open(file, 'w')  # touch
<open file 'C:\\...\\test.txt', mode 'w' at 0x00000000021951E0>
>>> os.path.isfile(path)
True
>>> os.path.isfile(path.upper())
True
>>> def isfile_casesensitive(path):
...    if not os.path.isfile(path): return False   # exit early
...    directory, filename = os.path.split(path)
...    return any(f == filename for f in os.listdir(directory))
...
>>> isfile_casesensitive(path)
True
>>> isfile_casesensitive(path.upper())
False