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Another way to access value(s) in a nested dictionary ( employees ) is to use the dict. get() method. This method returns the value for a specified key. If the specified key does not exist, the get() method returns None (preventing a KeyError ).
Use get() and Key to Check if Value Exists in a Dictionary Dictionaries in Python have a built-in function key() , which returns the value of the given key. At the same time, it would return None if it doesn't exist.
Access Nested Dictionary Items You can access individual items in a nested dictionary by specifying key in multiple square brackets. If you refer to a key that is not in the nested dictionary, an exception is raised. To avoid such exception, you can use the special dictionary get() method.
values() to check if a value is in a dictionary. Use dict. values() to get the values of a dictionary. Use the expression value in dictionary_values to return True if the value is in the dictionary and False if otherwise.
For a large list of nested dictionaries, I want to check if they contain or not a key. Each of them may or may not have one of the nested dictionaries, so if I loop this search through all of them raises an error:
for Dict1 in DictionariesList:
if "Dict4" in Dict1['Dict2']['Dict3']:
print "Yes"
My solution so far is:
for Dict1 in DictionariesList:
if "Dict2" in Dict1:
if "Dict3" in Dict1['Dict2']:
if "Dict4" in Dict1['Dict2']['Dict3']:
print "Yes"
But this is a headache, ugly, and probably not very resources effective. Which would be the correct way to do this in the first type fashion, but without raising an error when the dictionary doesnt exist?
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