Menu
Below is the file output:
apples:20 orange:100 Below is the code:
d = {} with open('test1.txt') as f: for line in f: if ":" not in line: continue key, value = line.strip().split(":", 1) d[key] = value for k, v in d.iteritems(): if k == 'apples': v = v.strip() if v == 20: print "Apples are equal to 20" else: print "Apples may have greater than or less than 20" if k == 'orrange': v = v.strip() if v == 20: print "orange are equal to 100" else: print "orange may have greater than or less than 100" In above code i am written "if k == 'orrange':", but its actually "orange" as per output file.
In this case I have to print orrange key is not exist in output file. Please help me. How to do this
254
Check If Key Exists Using has_key() The has_key() method is a built-in method in Python that returns true if the dict contains the given key, and returns false if it isn't.
Check if a key-value pair exists in a dictionary: in operator, items() To check if a key-value pair exists in a dictionary, i.e., if a dictionary has/contains a pair, use the in operator and the items() method. Specify a tuple (key, value) . Use not in to check if a pair does not exist in a dictionary.
The simplest way to check if a key exists in a dictionary is to use the in operator. It's a special operator used to evaluate the membership of a value. This is the intended and preferred approach by most developers.
Use the in keyword.
if 'apples' in d: if d['apples'] == 20: print('20 apples') else: print('Not 20 apples') If you want to get the value only if the key exists (and avoid an exception trying to get it if it doesn't), then you can use the get function from a dictionary, passing an optional default value as the second argument (if you don't pass it it returns None instead):
if d.get('apples', 0) == 20: print('20 apples.') else: print('Not 20 apples.') If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With