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' ' in word == True I'm writing a program that checks whether the string is a single word. Why doesn't this work and is there any better way to check if a string has no spaces/is a single word..
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Use the test() method to check if a string contains whitespace, e.g. /\s/. test(str) . The test method will return true if the string contains at least one whitespace character and false otherwise.
The isspace() function in C++ checks if the given character is a whitespace character or not.
The isWhitespace(char ch) method returns a Boolean value, i.e., true if the given(or specified) character is a Java white space character. Otherwise, this method returns false.
== takes precedence over in, so you're actually testing word == True.
>>> w = 'ab c' >>> ' ' in w == True 1: False >>> (' ' in w) == True 2: True But you don't need == True at all. if requires [something that evalutes to True or False] and ' ' in word will evalute to true or false. So, if ' ' in word: ... is just fine:
>>> ' ' in w 3: True Write if " " in word: instead of if " " in word == True:.
Explanation:
a < b < c is equivalent to (a < b) and (b < c).in!' ' in w == True is equivalent to (' ' in w) and (w == True) which is not what you want.
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