Checking if Array of Objects Includes Object We can use the some() method to search by object's contents. The some() method takes one argument accepts a callback, which is executed once for each value in the array until it finds an element which meets the condition set by the callback function, and returns true .
You'd have to compare the object, by comparing values of every property to decide whether it is in the array or not. Plain array. includes will compare the references. What makes you call the inserted object "the same"?
We are required to write a function containsAll() that takes in two arguments, first an object and second an array of strings. It returns a boolean based on the fact whether or not the object contains all the properties that are mentioned as strings in the array.
Using the indexOf() Method JavaScript's indexOf() method will return the index of the first instance of an element in the array. If the element does not exist then, -1 is returned.
I've assumed that id
s are meant to be unique here. some
is a great function for checking the existence of things in arrays:
const arr = [{ id: 1, username: 'fred' }, { id: 2, username: 'bill' }, { id: 3, username: 'ted' }];
function add(arr, name) {
const { length } = arr;
const id = length + 1;
const found = arr.some(el => el.username === name);
if (!found) arr.push({ id, username: name });
return arr;
}
console.log(add(arr, 'ted'));
It's rather trivial to check for existing username:
var arr = [{ id: 1, username: 'fred' },
{ id: 2, username: 'bill'},
{ id: 3, username: 'ted' }];
function userExists(username) {
return arr.some(function(el) {
return el.username === username;
});
}
console.log(userExists('fred')); // true
console.log(userExists('bred')); // false
But it's not so obvious what to do when you have to add a new user to this array. The easiest way out - just pushing a new element with id
equal to array.length + 1
:
function addUser(username) {
if (userExists(username)) {
return false;
}
arr.push({ id: arr.length + 1, username: username });
return true;
}
addUser('fred'); // false
addUser('bred'); // true, user `bred` added
It will guarantee the IDs uniqueness, but will make this array look a bit strange if some elements will be taken off its end.
This small snippets works for me..
const arrayOfObject = [{ id: 1, name: 'john' }, {id: 2, name: 'max'}];
const checkUsername = obj => obj.name === 'max';
console.log(arrayOfObject.some(checkUsername))
if you have array of elements like ['john','marsh']
then we can do some thing like this
const checkUsername = element => element == 'john';
console.log(arrayOfObject.some(checkUsername))
This is what I did in addition to @sagar-gavhane's answer
const newUser = {_id: 4, name: 'Adam'}
const users = [{_id: 1, name: 'Fred'}, {_id: 2, name: 'Ted'}, {_id: 3, name:'Bill'}]
const userExists = users.some(user => user.name === newUser.name);
if(userExists) {
return new Error({error:'User exists'})
}
users.push(newUser)
I think that, this is the shortest way of addressing this problem. Here I have used ES6 arrow function with .filter to check the existence of newly adding username.
var arr = [{
id: 1,
username: 'fred'
}, {
id: 2,
username: 'bill'
}, {
id: 3,
username: 'ted'
}];
function add(name) {
var id = arr.length + 1;
if (arr.filter(item=> item.username == name).length == 0){
arr.push({ id: id, username: name });
}
}
add('ted');
console.log(arr);
Link to Fiddle
There could be MULTIPLE POSSIBLE WAYS to check if an element(in your case its Object) is present in an array or not.
const arr = [
{ id: 1, username: 'fred' },
{ id: 2, username: 'bill' },
{ id: 3, username: 'ted' },
];
let say you want to find an object with id = 3.
1. find: It searches for an element in an array and if it finds out then it returns that element else return undefined. It returns the value of the first element in the provided array that satisfies the provided testing function. reference
const ObjIdToFind = 5;
const isObjectPresent = arr.find((o) => o.id === ObjIdToFind);
if (!isObjectPresent) { // As find return object else undefined
arr.push({ id: arr.length + 1, username: 'Lorem ipsum' });
}
2. filter: It searches for elements in an array and filters out all element that matches the condition. It returns a new array with all elements and if none matches the condition then an empty array. reference
const ObjIdToFind = 5;
const arrayWithFilterObjects= arr.filter((o) => o.id === ObjIdToFind);
if (!arrayWithFilterObjects.length) { // As filter return new array
arr.push({ id: arr.length + 1, username: 'Lorem ipsum' });
}
3. some: The some() method tests whether at least one element is present in an array that passes the test implemented by the provided function. It returns a Boolean value. reference
const ObjIdToFind = 5;
const isElementPresent = arr.some((o) => o.id === ObjIdToFind);
if (!isElementPresent) { // As some return Boolean value
arr.push({ id: arr.length + 1, username: 'Lorem ipsum' });
}
Let's assume we have an array of objects and you want to check if value of name is defined like this,
let persons = [ {"name" : "test1"},{"name": "test2"}];
if(persons.some(person => person.name == 'test1')) {
... here your code in case person.name is defined and available
}
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