Is there any ways we can detect if an object is list in python using type(obj)
--> list
.
But how can we detect if the object is list of list of the form as:
[['a','b']['a','b'][][]]
“not in” operator − This operator is used to check whether an element is not present in the passed list or not. Returns true if the element is not present in the list otherwise returns false.
The best way to checks if the object is a string is by using the isinstance() method in Python. This function returns True if the given object is an instance of class classified or any subclass of class info, otherwise returns False.
Check if Variable is a List with type() Now, to alter code flow programatically, based on the results of this function: a_list = [1, 2, 3, 4, 5] # Checks if the variable "a_list" is a list if type(a_list) == list: print("Variable is a list.") else: print("Variable is not a list.")
Use isinstance()
to check for a specific type:
>>> isinstance([], list)
True
Use all()
to test if all elements are of a certain type:
all(isinstance(elem, list) for elem in list_of_lists)
all()
short-circuits; if any of the tests returns False
, the loop is terminated and False
is returned. Only if all but one element returns True
does all()
need to examine every element of the iterable.
If you want to make sure that every item in your list is a list, you could do something like this:
if all(isinstance(i, list) for i in lst):
# All of the items are lists
isinstance(i, list)
is the better way of writing type(i) == type(list)
or type(i) == list)
.all()
returns True
if all of the items in the sequence are True
. It'll return False
if any aren't True
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