Menu
I mean Object-B is included in Object-A, when all attributes of Object-B are included in the object-A and its values are the same in the object-A.
var obj_b={a:1,d:3}
var obj_a={a:1,b:22,c:33,d:3} //--> obj_b includes in obj_a
var obj_c={a:1,f:4};
isIncluded=(small,big)=>Object.keys(small).every((k)=>big[k] === small[k])
console.log(
'Does "obj-b" included in "obj-a" ? ',isIncluded(obj_b,obj_a)
)
console.log(
'Does "obj-c" included in "obj-a" ? ',isIncluded(obj_c,obj_a)
)Does ES6/ES7 has built-in API more elegant and brief for that?
For example, to extend object from origin, ES6 brought Object.assign(o1,o2)?
Is there something like Object.isInclude(o1,o2)?
944
There is no way to tell the difference between an object built from an object literal, and one built from other means. It's a bit like asking if you can determine whether a numeric variable was constructed by assigning the value '2' or '3-1';
The hasOwnProperty() method will check if an object contains a direct property and will return true or false if it exists or not. The hasOwnProperty() method will only return true for direct properties and not inherited properties from the prototype chain.
Using the Object.Object. keys() is a static method that returns an Array when we pass an object to it, which contains the property names (keys) belonging to that object. We can check whether the length of this array is 0 or higher - denoting whether any keys are present or not.
To check if all values in object are equal to true :Use the Object. values() method to get an array of the object's values. Call the every() method on the array. The every method will test if all values in the array are equal to true and will return the result.
No, there is not. Your solution is already brief and elegant, although it could be golfed by another 4 characters.
const isSubObject = (small,big)=>Object.keys(small).every(k=>big[k]===small[k]);
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
