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I'm trying to do a simple test that returns True if any of the results of a list are None. However, I want 0 and '' to not cause a return of True.
list_1 = [0, 1, None, 4] list_2 = [0, 1, 3, 4] any(list_1) is None >>>False any(list_2) is None >>>False As you can see, the any() function as it is isn't being helpful in this context.
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Use the in operator to check if any item in a list is None, e.g. if None in my_list: . The in operator tests for membership. For example, x in l evaluates to True if x is a member of l , otherwise it evaluates to False .
None is not the same as 0, False, or an empty string. None is a data type of its own (NoneType) and only None can be None.
In this solution, we use the len() to check if a list is empty, this function returns the length of the argument passed. And given the length of an empty list is 0 it can be used to check if a list is empty in Python.
For list objects can simply use a membership test:
None in list_1 Like any(), the membership test on a list will scan all elements but short-circuit by returning as soon as a match is found.
any() returns True or False, never None, so your any(list_1) is None test is certainly not going anywhere. You'd have to pass in a generator expression for any() to iterate over, instead:
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