ArrayList. contains() method can be used to check if an element exists in an ArrayList or not. This method has a single parameter i.e. the element whose presence in the ArrayList is tested. Also it returns true if the element is present in the ArrayList and false if the element is not present.
To check if ArrayList contains a specific object or element, use ArrayList. contains() method. You can call contains() method on the ArrayList, with the element passed as argument to the method. contains() method returns true if the object is present in the list, else the method returns false.
Just use ArrayList.contains(desiredElement). For example, if you're looking for the conta1 account from your example, you could use something like:
if (lista.contains(conta1)) {
System.out.println("Account found");
} else {
System.out.println("Account not found");
}
Edit:
Note that in order for this to work, you will need to properly override the equals() and hashCode() methods. If you are using Eclipse IDE, then you can have these methods generated by first opening the source file for your CurrentAccount
object and the selecting Source > Generate hashCode() and equals()...
Better to use a HashSet
than an ArrayList
when you are checking for existence of a value.
Java docs for HashSet
says: "This class offers constant time performance for the basic operations (add, remove, contains and size)"
ArrayList.contains()
might have to iterate the whole list to find the instance you are looking for.
Please refer to my answer on this post.
There is no need to iterate over the List
just overwrite the equals
method.
Use equals
instead of ==
@Override
public boolean equals (Object object) {
boolean result = false;
if (object == null || object.getClass() != getClass()) {
result = false;
} else {
EmployeeModel employee = (EmployeeModel) object;
if (this.name.equals(employee.getName()) && this.designation.equals(employee.getDesignation()) && this.age == employee.getAge()) {
result = true;
}
}
return result;
}
Call it like this:
public static void main(String args[]) {
EmployeeModel first = new EmployeeModel("Sameer", "Developer", 25);
EmployeeModel second = new EmployeeModel("Jon", "Manager", 30);
EmployeeModel third = new EmployeeModel("Priyanka", "Tester", 24);
List<EmployeeModel> employeeList = new ArrayList<EmployeeModel>();
employeeList.add(first);
employeeList.add(second);
employeeList.add(third);
EmployeeModel checkUserOne = new EmployeeModel("Sameer", "Developer", 25);
System.out.println("Check checkUserOne is in list or not");
System.out.println("Is checkUserOne Preasent = ? " + employeeList.contains(checkUserOne));
EmployeeModel checkUserTwo = new EmployeeModel("Tim", "Tester", 24);
System.out.println("Check checkUserTwo is in list or not");
System.out.println("Is checkUserTwo Preasent = ? " + employeeList.contains(checkUserTwo));
}
We can use contains
method to check if an item exists if we have provided the implementation of equals
and hashCode
else object reference will be used for equality comparison. Also in case of a list contains
is O(n)
operation where as it is O(1)
for HashSet
so better to use later. In Java 8 we can use streams also to check item based on its equality or based on a specific property.
CurrentAccount conta5 = new CurrentAccount("João Lopes", 3135);
boolean itemExists = lista.stream().anyMatch(c -> c.equals(conta5)); //provided equals and hashcode overridden
System.out.println(itemExists); // true
String nameToMatch = "Ricardo Vitor";
boolean itemExistsBasedOnProp = lista.stream().map(CurrentAccount::getName).anyMatch(nameToMatch::equals);
System.out.println(itemExistsBasedOnProp); //true
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