Check if a number is a double or an int

Question

I am trying to beautify a program by displaying 1.2 if it is 1.2 and 1 if it is 1 problem is I have stored the numbers into the arraylist as doubles. How can I check if a Number is a double or int?

Answer 1

Well, you can use:

if (x == Math.floor(x))

or even:

if (x == (long) x) // Performs truncation in the conversion

If the condition is true, i.e. the body of the if statement executes, then the value is an integer. Otherwise, it's not.

Note that this will view 1.00000000001 as still a double - if these are values which have been computed (and so may just be "very close" to integer values) you may want to add some tolerance. Also note that this will start failing for very large integers, as they can't be exactly represented in double anyway - you may want to consider using BigDecimal instead if you're dealing with a very wide range.

EDIT: There are better ways of approaching this - using DecimalFormat you should be able to get it to only optionally produce the decimal point. For example:

import java.text.*;

public class Test
{
    public static void main(String[] args)
    {
        DecimalFormat df = new DecimalFormat("0.###");

        double[] values = { 1.0, 3.5, 123.4567, 10.0 };

        for (double value : values)
        {
            System.out.println(df.format(value));
        }
    }
}

Output:

1
3.5
123.457
10

Answer 2

Another simple & intuitive solution using the modulus operator (%)

if (x % 1 == 0)  // true: it's an integer, false: it's not an integer