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I am facing difficulty in comparing two double values using == and !=.
I have created 6 double variables and trying to compare in If condition.
double a,b,c,d,e,f;
if((a==b||c==d||e==f))
{
//My code here in case of true condition
}
else if ((a!=b||c!=d||e!=f))
{
//My code here in case false condition
}
Though my condition is a and b are equal control is going to else if part
So I have tried a.equals(b) for equal condition, Which is working fine for me.
My query here is how can I check a not equal b. I have searched the web but I found only to use != but somehow this is not working for me.
413
Using the == Operator As a result, we can't have an exact representation of most double values in our computers. They must be rounded to be saved. In that case, comparing both values with the == operator would produce a wrong result. For this reason, we must use a more complex comparison algorithm.
equals() is a built-in function in java that compares this object to the specified object. The result is true if and only if the argument is not null and is a Double object that contains the same double value as this object. It returns false if both the objects are not same.
The inequality operator ( != ) checks whether its two operands are not equal, returning a Boolean result.
If you're using a double (the primitive type) then a and b must not be equal.
double a = 1.0;
double b = 1.0;
System.out.println(a == b);
If .equals() works you're probably using the object wrapper type Double. Also, the equivalent of != with .equals() is
!a.equals(b)
Edit
Also,
else if ((a!=b||c!=d||e!=f))
{
//My code here in case false condition
}
(Unless I'm missing something) should just be
else
{
//My code here in case false condition
}
if you really want invert your test conditions and test again,
else if (!(a==b||c==d||e==f))
Or use De Morgan's Laws
else if (a != b && c != d && e != f)
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