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I have an object:
var Obj1 = {id: 1, name: 'Apple'}
And an array object:
var ArrObj = [ {id: 1, name: 'Apple', 'eat': 'rice}, {'id: 2', 'name': 'Banana'}]
How do I check Obj1.id in ArrObj? And I want the result to be: { id:1, name: 'Apple', 'eat':'rice'}
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JavaScript Array includes() The includes() method returns true if an array contains a specified value. The includes() method returns false if the value is not found.
isArray(variableName) method to check if a variable is an array. The Array. isArray(variableName) returns true if the variableName is an array. Otherwise, it returns false .
get() is an inbuilt method in Java and is used to return the element at a given index from the specified Array. Parameters : This method accepts two mandatory parameters: array: The object array whose index is to be returned.
The isArray() method returns true if an object is an array, otherwise false .
You can use Array.find():
var Obj1 = {id: 2, name: 'Banana'}
var ArrObj = [ {id: 1, name: 'Apple', 'eat': 'rice'}, {'id': 2, 'name': 'Banana'}];
var res = ArrObj.find(({id}) => id === Obj1.id );
console.log(res);You can also use array destructuring way like:
var Obj1 = {id: 2, name: 'Banana'}
var ArrObj = [ {id: 1, name: 'Apple', 'eat': 'rice'}, {'id': 2, 'name': 'Banana'}];
var res = ArrObj.find(({id}) => id === Obj1.id);
console.log(res);You could also use the filter function like this:
let result = ArrObj.filter(obj => {
return obj.id == Obj1.id
})
Documentation is here: Array.prototype.filter()
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