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Let's say I have some text in a variable called $1. Now I want to check if that $1 contains a certain string. If it contains a certain string I want to print a message. The printing is not the problem, the problem is the check. Any ideas how to do that?
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Use double percent signs ( %% ) to carry out the for command within a batch file. Variables are case sensitive, and they must be represented with an alphabetical value such as %a, %b, or %c. ( <set> ) Required. Specifies one or more files, directories, or text strings, or a range of values on which to run the command.
Using the findstr command lets you search for text within any plaintext file. Using this command within a batch file lets you search for text and create events off the results found.
You can run findstr from the command line or as a batch file. Open a new command line prompt by clicking on the Windows-key, typing cmd.exe, and selecting the result. Alternatively, use the Run command to open findstr.
The easiest way in my opinion is this :
set YourString=This is a test If NOT "%YourString%"=="%YourString:test=%" ( echo Yes ) else ( echo No ) Basiclly the string after ':' is the string you are looking for and you are using not infront of the if because %string:*% will remove the * from the string making them not equal.
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