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In C, you have to declare the length of an array:
int myArray[100];
But when you're dealing with chars and strings, the length can be left blank:
char myString[] = "Hello, World!";
Does the compiler generate the length for you by looking at the string?
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The first - arr object size is printed to be 24 bytes because the strlen function iterates through a char array until the terminating null byte is encountered.
Char Size. The size of both unsigned and signed char is 1 byte always, irrespective of what compiler we use. Here, a signed character is capable of holding negative values. Thus, the defined range here is -128 to +127.
The size of char is 1 byte, and wikipedia says: sizeof is used to calculate the size of any datatype, measured in the number of bytes required to represent the type. However, i can store 11 bytes in unsigned char array[10] 0.. 10 but when i do sizeof(array) i get 10 bytes.
We can find the size of an array using the sizeof() operator as shown: // Finds size of arr[] and stores in 'size' int size = sizeof(arr)/sizeof(arr[0]);
This is not unique to char. You could do this, for instance:
int myNumbers[] = { 5, 10, 15, 20, 42 };
This is equivalent to writing:
int myNumbers[5] = { 5, 10, 15, 20, 42 };
Initialising a char array from a string literal is a special case.
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Yes, it's the length including the terminating '\0'.
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