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Changing title and description of Swagger UI using Springfox

I am building a Spring Boot application and documenting it using a Swagger UI using the Springfox Swagger UI. I've got everything documented, but want to customize the title and description but can't figure out how. For example, in this image: https://springfox.github.io/springfox/docs/current/images/springfox-swagger-ui.png the title is "Springfox petstore API" and the description is Lorem Ipsum. But in my Swagger UI, both the title and the description say "API Documentation". I have tried using the @SwaggerDefinition annotation, but it does not seem to do anything.

like image 822
faiuwle Avatar asked Nov 09 '17 19:11

faiuwle


1 Answers

I recommend you to use swagger editor, then you can auto generate Spring Boot server from the API docs, using "Generate Server" option from Top Menu. It is really great for generating an API for the first time.

If you want to set from the YAML you must provide this fields at the info section:

info:
  version: "1.0.0"
  title: My API title
  description: "Awesome description"

From the code, check the generated classes from Swagger editor and compare it with your code. You could set description and title, setting the corresponding attributes on the ApiInfo Builder object, which is inside the class SwaggerDocumentationConfig.

Here you have the code:

@javax.annotation.Generated(value = "io.swagger.codegen.languages.SpringCodegen", date = "2017-10-05T14:03:51.916-03:00")

@EnableSwagger2
@Configuration
public class SwaggerDocumentationConfig {

    ApiInfo apiInfo() {
        return new ApiInfoBuilder()
            .title("My API Title")
            .description("Awesome description")
            .license("Apache 2.0")
            .licenseUrl("http://www.apache.org/licenses/LICENSE-2.0.html")
            .termsOfServiceUrl("")
            .version("1.0.0")
            .contact(new Contact("", "", "[email protected]"))
            .build();
    }

    @Bean
    public Docket customImplementation() {
        return new Docket(DocumentationType.SWAGGER_2)
            .select()
            .apis(RequestHandlerSelectors.basePackage("com.mypackage.api"))
            .build()
            .apiInfo(apiInfo());
    }
}

If none of this makes sense to you, show me a little more of your code to know how you are using Springfox and I can help you better.

Bests regards!

like image 73
Emiliano Viotti Avatar answered Nov 17 '22 15:11

Emiliano Viotti