EDIT: Since the question has became quite popular I will fix the problem so it will be working code example. The original problem is still listed, But the code works.
i am trying to show a div after pressing a button but this wont work, any idea why is that?
<form action="insert.php" method="POST" align="right" id="post_form">
<input type="button" value="click me" onClick="show()">
<div id="show_button"> fdsfds </div><br>
</form>
#show_button{
visibility:hidden;
}
function show(){
// alert("cheked the button - worked");
document.getElementById("show_button").style.visibility= 'visible' ;
}
Another way to make a div visible or invisible is with the display property. Then we can make it visible with: const div = document. querySelector('div') div.
The document. getElementById will select the div with given id. The style. display = "none" will make it disappear when clicked on div.
The hidden attribute hides the <div> element. You can specify either 'hidden' (without value) or 'hidden="hidden"'. Both are valid. A hidden <div> element is not visible, but it maintains its position on the page.
Change your CSS to:
#show_button{
display: none
}
And you in your javascript:
function show(){
//alert("cheked the button - worked");
document.getElementById('show_button').style.display= 'block' ;
}
Typo error change it document.getElementById(show_button)
to document.getElementById("show_button")
function show(){
document.getElementById("show_button").style.visibility= "visible" ;
}
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