Change specific RGB color pixels to another color, in image file

Question

I would like to change a single color with Python.

If a fast solution with PIL exists, I would prefer this solution.

At the moment, I use

convert -background black -opaque '#939393' MyImage.png MyImage.png

Answer 1

If numpy is available on your machine, try doing something like:

import numpy as np
from PIL import Image

im = Image.open('fig1.png')
data = np.array(im)

r1, g1, b1 = 0, 0, 0 # Original value
r2, g2, b2 = 255, 255, 255 # Value that we want to replace it with

red, green, blue = data[:,:,0], data[:,:,1], data[:,:,2]
mask = (red == r1) & (green == g1) & (blue == b1)
data[:,:,:3][mask] = [r2, g2, b2]

im = Image.fromarray(data)
im.save('fig1_modified.png')

It will use a bit (3x) more memory, but it should be considerably (~5x, but more for bigger images) faster.

Also note that the code above is slightly more complicated than it needs to be if you only have RGB (and not RGBA) images. However, this example will leave the alpha band alone, whereas a simpler version wouldn't have.

Answer 2

This is a modification of Joe Kington's answer above. The following is how to do this if your image contains an alpha channel as well.

import numpy as np
import Image

im = Image.open('fig1.png')
im = im.convert('RGBA')
data = np.array(im)

r1, g1, b1 = 0, 0, 0 # Original value
r2, g2, b2, a2 = 255, 255, 255, 255 # Value that we want to replace it with

red, green, blue, alpha = data[:,:,0], data[:,:,1], data[:,:,2], data[:,:,3]
mask = (red == r1) & (green == g1) & (blue == b1)
data[:,:,:4][mask] = [r2, g2, b2, a2]

im = Image.fromarray(data)
im.save('fig1_modified.png')

It took me a long time to figure out how to get it to work. I hope that it helps someone else.