I just learn react, and want to achieve a function : both A,B are components, if A scroll, then B scroll
The following is my code
<A onScroll="handleScroll"></A>
//what i write now
handleScroll: function(event){
var target = event.nativeEvent.target;
//do something to change scrollTop value
target.scrollTop += 1;
// it looks the same as not use react
document.getElementById(B).scrollTop = target.scrollTop;
}
but actually I want my code like this
//what i want
<A scrollTop={this.props.scrollSeed}></A>
<B scrollTop={this.props.scrollSeed}></B>
//...
handleScroll(){
this.setState({scrollSeed: ++this.state.scrollSeed})
}
it is similar to input
<input value="this.props.value"/>
<input value="this.props.value"/>
<input ref='c' onChange={handleChange}>
//...
handleChange: function() {
// enter some code in c and then render in a and b automatically
}
In other words, I want some attribute, like scrollTop
(different
form <input value={}>
,because <A scrollTop={}>
doesn't work) ,is bind with some state, so that I can just use setState
, and they will update by themselves.
I googled before but can't find the answser. I hope that my poor English won't confuse you.
Use the window. scrollTo() method to scroll to the top of the page in React, e.g. window. scrollTo(0, 0) . The scrollTo method on the window object scrolls to a particular set of coordinates in the document.
U need to set window. scrollTo(0, 0) when u click on link so it would start on top of page.
The most simple way is to use ref to store the reference of the element that you want to scroll to. And call myRef. current. scrollIntoView() to scroll it into the view.
There are a number of patterns to achieve this. This sample is what I came up with to get you up and going.
First create a component class which has an oversize element for scroll effect. When dragging the scroll bar, this component calls its handleScroll
React property to notify its parent component, with the value of scrollTop
.
var Elem = React.createClass({
render() {
return (
<div ref="elem"
onScroll={ this.onScroll }
style={{ width: "100px", height: "100px", overflow: "scroll" }}>
<div style={{ width: "100%", height: "200%" }}>Hello!</div>
</div>
);
},
componentDidUpdate() {
this.refs.elem.scrollTop = this.props.scrollTop;
},
onScroll() {
this.props.handleScroll( this.refs.elem.scrollTop );
}
});
The parent component, aka wrapper, keeps the scroll top value in its state. Its handleScroll
is passed to the child components as callback. Any scroll on the child elements triggers the callback, sets the state, results in a redraw, and updates the child component.
var Wrapper = React.createClass({
getInitialState() {
return {
scrollTop: 0
}
},
render() {
return (
<div>
<Elem scrollTop={ this.state.scrollTop } handleScroll={ this.handleScroll } />
<Elem scrollTop={ this.state.scrollTop } handleScroll={ this.handleScroll } />
</div>
);
},
handleScroll( scrollTop ) {
this.setState({ scrollTop });
}
});
And render the wrapper, presuming an existing <div id="container"></div>
.
ReactDOM.render(
<Wrapper />,
document.getElementById('container')
);
First, the fix:
const resetScrollEffect = ({ element }) => {
element.current.getScrollableNode().children[0].scrollTop = 0
}
const Table = props => {
const tableRef = useRef(null)
useEffect(() => resetScrollEffect({ element: tableRef }), [])
return (
<Component>
<FlatList
ref={someRef}
/>
</Component>
)
}
Second, a little explanation:
Idk what is your reason why you got here but I have used flex-direction: column-reverse
for my FlatList (it's a list of elements). And I need this property for z-index
purposes. However, browsers set their scroll position to the end for such elements (tables, chats, etc.) - this may be useful but I don't need that in my case.
Also, example is shown using React Hooks, but you can use older more traditional way of defining refs
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