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Change list link to foreign key change page

When viewing the admin change list for a model, is it possible to make the columns that correspond to foreign keys links to their respective pages? A simple example is I have a Foo object which contains Bar as a foreign key. If I'm viewing the admin change list for Foo (and have it set to include Bar in the display_list columns), the main column would link to the Foo instance's edit page while the Bar column would link to the Boo instance's edit page. I understand I can override the template that's used, but I was curious if there was a solution that didn't require that.

like image 524
Adam Avatar asked Sep 12 '09 00:09

Adam


2 Answers

You can define a custom method to use in the changelist which returns the HTML of the link.

from django.core.urlresolvers import reverse

class MyFooAdmin(admin.ModelAdmin):
    list_display = ('foo', 'bar_link')

    def bar_link(self, obj):
        url = reverse('admin:myapp_bar_change', args=(obj.pk,))
        return '<a href="%s">Edit Bar</a>' % url 
    bar_link.allow_tags = True 

One problem with your question as stated - if Foo has a foreign key to Bar, then each foo links to a single bar, so you can link to the edit page for that bar. However, each bar links to multiple foos, so it doesn't make sense to ask for a link to 'the Foo instance's edit page'. What you can do is link to the changelist page for Foo with the filter set to only show the instances that link to this Bar:

    def foo_link(self, obj):
        url = reverse('admin:myapp_foo_changelist')
        return '<a href="%s?bar=%s">See Foos</a>' % (url, obj.pk) 
    foo_link.allow_tags = True 
like image 83
Daniel Roseman Avatar answered Oct 19 '22 14:10

Daniel Roseman


I found and liked Daniel's answer, although the changelist variant clears away any changes you've already done. So this is a way to fix that:

First you need to get a reference to the request, you can do that by wrapping changelist_view or queryset as I did:

class CountryAdmin(ModelAdmin):
    model = Country
    list_display = ('pk', 'continent_changelist')

    # ...

    def queryset(self, request):
        self._get_params = request.GET
        return super(CountryAdmin, self).queryset(request)

    def continent_changelist(self, obj):
        url = reverse('admin:yourapp_country_changelist')
        querystring = self._get_params.copy()
        querystring['continent__id__exact'] = obj.continent.pk
        return u'<a href="{0}?{1}">{2}</a>'.format(
            url, querystring.urlencode(), obj.continent)
    continent_changelist.allow_tags = True

That will give you a filter inside the changelist rows. I answered this in another question, but this was the place I actually came first, so wanted to record it here. :-)

like image 39
odinho - Velmont Avatar answered Oct 19 '22 13:10

odinho - Velmont