Change length of operation depending on a value

Question

Context

I am trying to create a program that gets the product of all n pairs in a number reading from left to right

For example, in the number 2345678:

• The product of all 2 pairs would be 2*3 = 6, 3*4=12, 4*5=20, 5*6=30 etc...
• The product of all 3 pairs would be 2*3*4=24,3*4*5=60, 4*5*6=120 etc...

I have completed most of the solution to the problem, but I cannot create an operation that can adapt for any value of n

Code

num = 2345678
num = str(num)


n = 2
start_pos = 0

for i in range(start_pos,len(num)):
    try:
        x += 1
        t = int(num[i]) * int(num[i+1]) # hardcoded for n = 2
        print(t)
        start_pos += 1
    except IndexError:
        break

Operation for different n values

n = 2: t = int(num[i]) * int(num[i+1])

n = 3: t = int(num[i]) * int(num[i+1]) * int(num[i+2])

n = 4: t = int(num[i]) * int(num[i+1]) * int(num[i+2]) * int(num[i+3])

n = 5: t = int(num[i]) * int(num[i+1]) * int(num[i+2]) * int(num[i+3]) * int(num[i+4])

How could I create an operation that can adapt for any value of n?

Answer 1

If you want an iterative solution without using any pythonic operator, you can simply add an inner for to iterate from i to i+n, and then accumulate the product of numbers in a variable t. Like this:

num = 2345678
num = str(num)


n = 3
start_pos = 0
x = 0
for i in range(start_pos,len(num)):
    try:

        t = 1
        for j in range(i, i+n):
            t = t * int(num[j])

        print(t)

    except IndexError:
        break

Output:

24
60
120
210
336