Change a url parameter

Question

How change a parameter's value of url? Without regexps.

Now I try this, but it's long:

from urllib.parse import parse_qs, urlencode,  urlsplit
url = 'http://example.com/?page=1&text=test#section'
param, newvalue = 'page', '2'

url, sharp, frag = url.partition('#')
base, q, query = url.partition('?')
query_dict = parse_qs(query)
query_dict[param][0] = newvalue
query_new = urlencode(query_dict, doseq=True)
url_new = f'{base}{q}{query_new}{sharp}{frag}'

Also, I tried by urlsplit:

parsed = urlsplit(url)
query_dict = parse_qs(parsed.query)
query_dict[param][0] = newvalue
query_new = urlencode(query_dict, doseq=True)
parsed.query = query_new
url_new = urlencode(parsed)

But on urlparsed.query = query_new it rise error AttributeError: can't set attribute.

Answer 1

Tuples are immutable.So you have to replace it .Here _ is meant to avoid conflict with fieldnames ._replace

from urllib.parse import parse_qs, urlencode,  urlsplit
url = 'http://example.com/?page=1&text=test#section'
param, newvalue = 'page', '2'
parsed = urlsplit(url)
query_dict = parse_qs(parsed.query)
query_dict[param][0] = newvalue
query_new = urlencode(query_dict, doseq=True)
parsed=parsed._replace(query=query_new)
url_new = (parsed.geturl())