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Casting boost::units::quantity to double

I need to pass the value of a quantity to a library for evaluation. The boost units library takes double values in SI, so the boost units library is very appealing in ensuring that requirement. However, how should I cast the quantity to a double value? The documentation and example seems to avoid this since the intent is to, rightfully so, maintain the units.

Something like:

quantity<pressure> p(101.1 * kilo * pascals);
double dblP = static_cast<double>(p);  // double value in Pascals 

Going through the headers suggests... Is that the correct way to cast to the base type?

p.value();
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ccook Avatar asked Dec 18 '12 16:12

ccook


3 Answers

I think what you're looking for is this:

quantity<pressure> p(101.1 * kilo * pascals);
double dblP = p / pascals;  // double value in Pascals 

If you divide out the unit, you are left with a quantity<dimensionless> which will implicitly convert to a double. This eliminates any question of what the internal representation (which value() returns) units are.

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wjl Avatar answered Nov 10 '22 12:11

wjl


Just spotted this. I think the intended method is to use Boost's quantity_cast operator.

quantity<pressure> p(101.1 * kilo * pascals);
double dblP = quantity_cast<double>(p);

http://www.boost.org/doc/libs/1_55_0/doc/html/boost_units/Quantities.html#boost_units.Quantities.Quantity_Construction_and_Conversion

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Alex Valavanis Avatar answered Nov 10 '22 11:11

Alex Valavanis


The reference documentation shows that either implicit casts or the value() member method can be used.

  1. operator value_type() const;

    implicit conversion to value_type is allowed

  2. const value_type & value() const;

    constant accessor to value

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R. Martinho Fernandes Avatar answered Nov 10 '22 10:11

R. Martinho Fernandes