I have a function
func doStuff(inout *interface{}) {
...
}
the purpose of this function is to be able to treat a pointer of any type as input. But when I want to call it with a the pointer of a struct I have an error.
type MyStruct struct {
f1 int
}
When calling doStuff
ms := MyStruct{1}
doStuff(&ms)
I have
test.go:38: cannot use &ms (type *MyStruct) as type **interface {} in argument to doStuff
How can I cast &ms
to be compatible with *interface{}
?
We can define interfaces considering the different actions that are common between multiple types. In Go, we can automatically infer that a struct (object) implements an interface when it implements all its methods.
Go's interface values are really a pair of pointers. When you put a concrete value into an interface value, one pointer starts pointing at the value. The second will now point to the implementation of the interface for the type of the concrete value.
Access struct using pointer in Golang In the above example, we have used the struct type pointer to access struct members: ptr.name - gives the value of the name member.
Structs and interfaces are Go's way of organizing methods and data handling. Where structs define the fields of an object, like a Person's first and last name. The interfaces define the methods; e.g. formatting and returning a Person's full name.
There is no such thing as a "pointer to an interface" (technically, you can use one, but generally you don't need it).
As seen in "what is the meaning of interface{} in golang?", interface
is a container with two words of data:
So remove the pointer, and doStuff
will work just fine: the interface data will be &ms
, your pointer:
func doStuff(inout interface{}) { ... }
See this example:
ms := MyStruct{1} doStuff(&ms) fmt.Printf("Hello, playground: %v\n", ms)
Output:
Hello, playground: {1}
As newacct mentions in the comments:
Passing the pointer to the interface directly works because if
MyStruct
conforms to a protocol, then*MyStruct
also conforms to the protocol (since a type's method set is included in its pointer type's method set).In this case, the interface is the empty interface, so it accepts all types anyway, but still.
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