Capturing named groups in regex with re.findall

Question

When I was trying to answer this question: regex to split %ages and values in python I noticed that I had to re-order the groups from the result of findall. For example:

data = """34% passed 23% failed 46% deferred"""
result = {key:value for value, key in re.findall('(\w+)%\s(\w+)', data)}
print(result)
>>> {'failed': '23', 'passed': '34', 'deferred': '46'}

Here the result of the findall is:

>>> re.findall('(\w+)%\s(\w+)', data)
>>> [('34', 'passed'), ('23', 'failed'), ('46', 'deferred')]

Is there a way to change/specify the order of the groups that makes re.findall return:

[('passed', '34'), ('failed', '23'), ('deferred', '46')]

Just to clarify, the question is:

Is it possible to specfic the order or re-order the groups for the return of the re.findall function?

I used the example above to create a dictionary to provide a reason/use case for when you would want to change the order (making key as value and value as key)

Further clarification:

In order to handle groups in larger more complicated regexes, you can name groups, but those names are only accessible when you do a re.search pr re.match. From what I have read, findall has a fixed indices for groups returned in the tuple, The question is anyone know how those indices could be modified. This would help make handling of groups easier and intuitive.

Answer 1

Take 3, based on a further clarification of the OP's intent in this comment.

Ashwin is correct that findall does not preserve named capture groups (e.g. (?P<name>regex)). finditer to the rescue! It returns the individual match objects one-by-one. Simple example:

data = """34% passed 23% failed 46% deferred"""
for m in re.finditer('(?P<percentage>\w+)%\s(?P<word>\w+)', data):
    print( m.group('percentage'), m.group('word') )