capturing group VS non-capturing group

Question

I tried to test the performance of capturing and non-capturing group of the regex. By the way, there is very slightly different between the capturing group and the non-capturing group. Is this result normal?

[root@Sensor ~]# ll -h sample.log
-rw-r--r-- 1 root root 21M Oct 20 23:01 sample.log

[root@Sensor ~]# time grep -ciP '(get|post).*' sample.log
20000

real    0m0.083s
user    0m0.070s
sys     0m0.010s

[root@Sensor ~]# time grep -ciP '(?:get|post).*' sample.log
20000

real    0m0.083s
user    0m0.077s
sys     0m0.004s

Answer 1

Typically, non-capturing groups perform better than capturing groups, because they require less allocation of memory, and do not make a copy of the group match. However, there are three important caveats:

• The difference is typically very small for simple, short expressions with short matches.
• The act of starting a program like grep itself takes a significant amount of time and memory, and may overwhelm any small improvement gained by using non-capturing group(s).
• Some languages implement capturing and non-capturing groups in the same way, causing the latter to give no performance improvement.

Answer 2

If use a lot of the capturing group. The difference seems to be more.

Thanks everyone.:)

[root@Sensor ~]# time grep -ciP "(get|post)\s[^\s]+" sample.log
20000

real    0m0.057s
user    0m0.051s
sys     0m0.005s
[root@Sensor ~]# time grep -ciP "(?:get|post)\s[^\s]+" sample.log
20000

real    0m0.061s
user    0m0.053s
sys     0m0.006s
[root@Sensor ~]# time grep -ciP "(get|post)\s[^\s]+(get|post)" sample.log
1880

real    0m0.839s
user    0m0.833s
sys     0m0.005s
[root@Sensor ~]# time grep -ciP "(?:get|post)\s[^\s]+(?:get|post)" sample.log
1880

real    0m0.744s
user    0m0.741s
sys     0m0.003s