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I'm compiling the code below and for some reason I can't assign -2147483648 to the variable which is 8 bytes long and signed.
long long x = -2147483648;
When I step over this line, the value of x is 2147483648 and the 'Watch' window in MS Visual Studio shows that the type of x is __int64. A sizeof(x) also returns 8.
According to limit.h the limits for a signed long long are:
#define LLONG_MAX 9223372036854775807i64 /* maximum signed long long int value */
#define LLONG_MIN (-9223372036854775807i64 - 1) /* minimum signed long long int value */
and:
/* minimum signed 64 bit value */
#define _I64_MIN (-9223372036854775807i64 - 1)
/* maximum signed 64 bit value */
#define _I64_MAX 9223372036854775807i64
I just don't get it!!!
Can somebody please shed some light on this?
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A long int typically uses twice as many bits as a regular int, allowing it to hold much larger numbers. printf and scanf replace %d or %i with %ld or %li to indicate the use of a long int. long int may also be specified as just long.
You can declare and initialize a Long variable by assigning it a decimal literal, a hexadecimal literal, an octal literal, or (starting with Visual Basic 2017) a binary literal. If the integer literal is outside the range of Long (that is, if it is less than Int64.
In terms of converting a ( signed ) long long datatype to an unsigned int in C and C++, you can simply cast the data between them: int main()
Without the LL, the compiler appears to deduce 2147483648 is a 32-bit unsigned long. Then it applies the - operator. The result is 0 - 2147483648. Since this is less than 0 and being an unsigned long t, 4294967296 is added, which is 2147483648 again. This value is then assigned to long long x.
Suggest:
long long x = -2147483648LL;
// or
long long x = -2147483647 - 1;
Try assigning to -2147483648LL
see Integer constants here
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