Cannot call pointer to member function from static method

Question

I am having difficulty calling a pointer to a member function on an object that was cast from void*. See below example:

class Test
{
public:
    Test(int pointTo)
    {
        if (pointTo == 1)
            function = &Test::Function1;
        else
            function = &Test::Function2;
    }

    static void CallIt(void* cStyle)
    {
        Test* t(static_cast<Test*>(cStyle));
        (t->*function)();// error C2568: '->*': unable to resolve function overload
    }

    void CallIt()
    {
        (this->*function)();// Works just fine
    }

private:
    typedef void (Test::*ptrToMemberFunc)();

    ptrToMemberFunc function;

    void Function1()
    {
        std::cout << "Function 1" << std::endl;
    }

    void Function2()
    {
        std::cout << "Function 2" << std::endl;
    }
};

int main()
{
    Test t1(1);
    Test t2(2);

    Test::CallIt(static_cast<void*>(&t1));
    Test::CallIt(static_cast<void*>(&t2));

    t1.CallIt();
    t2.CallIt();

    return 0;
}

What happens when the object is cast to void* and back? Why can I no longer call the pointer to member function?

EDIT:

Modifying CallIt() as follows allows the program to compile, but I'm still curious as to why the original didn't work.

static void CallIt(void* cStyle)
{
    Test* t(static_cast<Test*>(cStyle));
    Test::ptrToMemberFunc pf(t->function);
    (t->*pf)();
}

Answer 1

main.cpp:17:14: error: invalid use of member 'function' in static member function
        (t->*function)();// error C2568: '->*': unable to resolve function overload
             ^~~~~~~~

function is a non-static data member, so you cannot access it from a static function.

If you want to refer to t's function, you can do it like so:

        (t->*(t->function))();