I want to make a program that takes 4 numbers eg.(a, b, c and d) and checks if using arithmetic operators i can make the first 3 numbers result to the fourth number, like if the input is (3, 4, 5, 23) this will check out true because 3 + 4 * 5 = 23,So i want to make an array that has the operators and use a loop to check every possible combination, Hope i made it clear.
Edit:
Its actually codeforces problem, given 4 numbers. Check whether he could get the fourth number by using the arithmetic operators (+,−,×) between the other three numbers. Knowing that an operator can be used only once. in this format ->(a□b□c=d).My question was if there is a way to make it automatic or do i have to code every possibility manually So sorry for any confusion i may have caused.
You can't store the operators in an array, but you could make wrapper functions for them and store those in an array.
int add(int a, int b) {
return a + b;
}
int sub(int a, int b) {
return a - b;
}
int mul(int a, int b) {
return a * b;
}
int div(int a, int b) {
return a / b;
}
typedef int (*funptr)(int, int);
funptr arr[] = { add, sub, mul, div };
You can then call them like:
(arr[1])(2, 1) // call sub(2, 1)
The parentheses around arr[1]
aren't needed in this case, but I like to put them for clarity.
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