Can you replace & with bitand in references?

Question

In C++, we can write and for &&, or for ||, bitand for & and bitor for |.

Now I wonder whether and and bitand are only valid where those operators are meant, or also where references are defined (g++ 4.6.3 accepts bitand for references — rvalue references seem not to be supported in that version — but of course that might just be the compiler not catching the error).

In short: Is the following code valid C++?

int and x = 3;

int a;
int bitand y = a;

Of course I would never write such code (except maybe if participating in an obfuscated code contest), but is it actually valid?

Answer 1

According to C++11, 2.6/4:

In all respects of the language, each alternative token behaves the same, respectively, as its primary token

So int and a = 5; is perfectly valid, though also perfectly insane.

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More examples:

struct ete
{
    compl ete();
    int egr()and;
};