Can you print anything in C++, before entering into the main function?

Question

Can you print anything in C++, before entering into the main function?

It is interview question in Bloomberg:

Answer :create a global variable assigning value from printf statement with some content.

Answer 1

#include <iostream>

std::ostream & o = (std::cout << "Hello\n");

int main()
{
   o << "Now main() runs.\n";
}

Answer 2

#include <iostream>
struct X
{
   X() 
   {
       std::cout << "Hello before ";
   }
} x;

int main()
{
   std::cout << "main()";
}

This well-formed C++ program prints

Hello before main()

You see, the C++ standard guarantees that the constructors of namespace-scope variables (in this example, it's x) will be executed before main(). Therefore, if you print something in a constructor of such an object, it will be printed before main(). QED