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Can you pass an 'expanded' array to a function in C# like in ruby?

Tags:

methods

c#

In ruby you can do something like this:

def method(a, b) ... end
myMethod(*myArray)

So if myArray had 2 items, it would be the equivalent of this:

myMehtod(myArray[0], myArray[1])

So that in the method body, a == myArray[0] and b == myArray[1]

Can you do this in C#? (So I can have a method declared with explicit arguments, instead of just taking an array as the argument)

EDIT: I should've been more specific about the method being called.

like image 723
Daniel Huckstep Avatar asked Oct 31 '09 22:10

Daniel Huckstep


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1 Answers

Your method can be declared to accept a parameter array, via params:

void F(params int[] foo) {
    // Do something with foo.
}

Now you can either pass a arbitrary number of ints to the method, or an array of int. But given a fixed method declaration, you cannot expand an array on-the-fly as you can in Ruby, because the parameters are handled differently under the hood (I believe this is different in Ruby), and because C# isn’t quite as dynamic.

Theoretically, you can use reflection to call the method to achieve the same effect, though (reflected method calls always accept a parameter array).

like image 77
Konrad Rudolph Avatar answered Oct 11 '22 14:10

Konrad Rudolph