Can you dynamically create the arguments for the zip() function in python 2?

Question

I am passing in a variable number of lists in *args to a function. What I'd like to accomplish is to pass this args to zip().

def amv(db, *args):
    x = zip(args)
    return x

I would like to avoid the following:

if len(args) == 1:
    x = zip(args[1])
elif len(args) == 2:
    x = zip(args[1], args[2])
...etc.

Answer 1

Erm... you almost have it.

x = zip(*args)