Can this be written as a python reduce function?

Question

Can you make this more pythonic by using the map and/or reduce functions? it just sums the products of every consecutive pair of numbers.

topo = (14,10,6,7,23,6)
result = 0
for i in range(len(topo)-1):
    result += topo[i]*topo[i+1]

Answer 1

This is the nicest way I can think of:

import operator
sum(map(operator.mul, topo[:-1], topo[1:]))

Edit: I've just found out there's a better way to do this:

import operator
import itertools

def pairwise(iterable):
    a, b = itertools.tee(iterable)
    next(b, None)
    return a, b

def sum_products(l):
    return sum(itertools.imap(operator.mul, *pairwise(l)))

Credit for pairwise function goes to the itertools documentation.

This is faster and uses less memory. Of course, it's less concise.