can php function parameters be passed in different order as defined in declaration

Question

Suppose I have a function/method F() that takes 3 parameters $A, $B and $C defined as this.

function F($A,$B,$C){
  ...
}

Suppose I don't want to follow the order to pass the parameters, instead can I make a call like this?

F($C=3,$A=1,$B=1);

instead of

F(1,2,3)

Answer 1

Starting with php@8, php will suppport named arguments.

This will allow passing arguments in a different order as long as you provide their name when calling.

E.g. this may look like:

class SomeDto
{
    public function __construct(
        public int $foo = 'foo',
        public string $bar = 'bar',
        public string $baz = 'baz',
    ) {}
}

$example = new SomeDto($bar = 'fnord!');
// will result in an object { foo: 'foo', bar: 'fnord!', baz: 'baz'}

Answer 2

Absolutely not.

One way you'd be able to pass in unordered arguments is to take in an associative array:

function F($params) {
   if(!is_array($params)) return false;
   //do something with $params['A'], etc...
}

You could then invoke it like this:

F(array('C' => 3, 'A' => 1, 'B' => 1));