In my DataFrame I wish to clip the value of a particular column between 0 and 100. For instance, given the following:
a b
0 10 90
1 20 150
2 30 -30
I want to get:
a b c
0 10 90 90
1 20 150 100
2 30 -30 0
I know that in Pandas certain arithmetic operations work across columns. For instance, I could double every number in column b
like so:
>>>df["c"] = df["b"] * 2
>>>df
a b c
0 10 90 180
1 20 150 300
2 30 -30 -60
However this doesn't work for built-in functions like min
and max
:
>>>df["c"] = min(100, max(0, df["b"]))
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
Is there some way to accomplish what I want efficiently?
Pandas DataFrame min() Method The min() method returns a Series with the minimum value of each column. By specifying the column axis ( axis='columns' ), the max() method searches column-wise and returns the minimum value for each row.
The short answer is yes, there is a size limit for pandas DataFrames, but it's so large you will likely never have to worry about it. The long answer is the size limit for pandas DataFrames is 100 gigabytes (GB) of memory instead of a set number of cells.
Method 2: Using set_option() A function set_option() is provided by pandas to display all rows of the data frame. display. max_rows represents the maximum number of rows that pandas will display while displaying a data frame. The default value of max_rows is 10.
display. max_rows and display. max_columns sets the maximum number of rows and columns displayed when a frame is pretty-printed.
You can use the Pandas min function across an axis. Then combine it with min/max
https://pandas.pydata.org/pandas-docs/stable/generated/pandas.DataFrame.min.html
For example
df.max(axis=1)
But it looks like you want to clip the values instead of min/max.
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