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Can not create a local and remote branch (tracking) at the same time

From Pro Git:

you can set up other tracking branches if you wish — ones that don’t track branches on origin and don’t track the master branch. The simple case is the example you just saw, running git checkout -b [branch] [remotename]/[branch]

$ git checkout --track origin/serverfix Branch serverfix set up to track remote branch refs/remotes/origin/serverfix. Switched to a new branch "serverfix"

$ git checkout -b sf origin/serverfix Branch sf set up to track remote branch refs/remotes/origin/serverfix. Switched to a new branch "sf"

My understanding is that this presents a way to create a local branch and an upstream branch.

But when I do:

git checkout -b iss53 origin/iss53 I get:
fatal: Cannot update paths and switch to branch 'iss53' at the same time.

And when I do:
git checkout --track origin/iss53 I get:

fatal: Cannot update paths and switch to branch 'iss53' at the same time. Did you intend to checkout 'origin/iss53' which can not be resolved as commit?

Why?

like image 539
Jim Avatar asked Jun 16 '13 20:06

Jim


1 Answers

Cannot update paths and switch to branch

As I mention in "Get new upstream branch with git", you can try:

# let's create a new local branch first
git checkout -b iss53
# then reset its starting point
git reset --hard origin/iss53 

Make sure that the remote tracking branch origin/iss53 does exist first (after a git fetch origin)

origin/iss53 means there was a iss53 on the upstream remote repo referenced by origin.

If there was not such a branch, then you only create a local branch iss53, and push it like so:

git push -u origin iss53 

That would establish an association between the local branch iss53 and the remote tracking branch origin/iss53 (tracking the newly created branch iss53 on origin, created by the push).

See "Why do I need to explicitly push a new branch?" for more on that initial push.

like image 169
VonC Avatar answered Oct 23 '22 10:10

VonC